已知A,B均为钝角且sinA=根号5/5,sinB=根号10/10 则A+B=?A,B均为钝角且sinA=根号5/5,则cosA=-根号(1-sinA^2)=-2根号5/5,sinB=根号10/10cosB=-根号(1-sinB^2)=-3根号10/10cos(A+B)=cosAcosB-sinAsinB=(-2根号5/5)*(-3根号10/10)-(根

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