1/1 -1/3 2/3 -3/3 -2/5 3/5 -4/5 5/5 -1/7 2/7 -3/7 …… 求 98个是多少

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1+2-3-3-3-3=? 2 1 -2 -3 1,1,1,2,2,2,3,3,3,填三阶幻方 （1+1/2+1/3+... 1+3+2+1+1x2+3 1,1/2,3/2,3/8,( ),( ) 1+1+2+2+3+3+````````````````````````````+99999 [(2^3-1)(3^3-1)...100^3-1)]/[(2^3+1)(3^3+1)...(100^3+1)]=? 1/(2^3)+1/(2^3+1)+1/(2^3+2)+1/(2^3+3)+...+1/(2^4-1) 1^3+2^3+3^3+...+99^3+100^3 (-1/3)^2除以(-1/3)^3*(1/3)^3除以3^-2*(-3)^0 3题 1、2、3 求和Sn=1+(1+3)+(1+3+3^2)+(1+3+3^2+3^3)+.+(1+3+3^2+3^3+...+3^n-1) (3+1)(3^2+1)(3^3+1)(3^4+1)…(3^32+1)步骤 求四阶行列式：2 -1 3 2 3 -3 3 2 3 -1 -1 2 3 -1 3 -1 求证1/1+1/2^(3/2)+1/3^(3/2)…+1/n^(3/2) （1/2+1/3)÷(2/3-3/2)=? -1-{(-3)²-[3+(2/3)*(-3/2)]/(-2)} 计算