Y=sin^2x+sin2x+2cos^2x化简

y=根号2sin2x变换到sin^2x+sin2x+2cos^2x 证明tan(x+y)+tan(x-y)=sin2x/cos^2x-sin^2y 证明sin2x+sin2y=2sin(x+y)cos(x-y)怎么做 sin2x+sin2y=2sin(x+y)cos(x-y) 怎么算? sin2x+sin2y=2sin（x+y）cos（x-y）怎么得的 y=sin^2x-3sinxcosx+4cos^2x是否等于y=sin^2x+cos^2x+3cos^2x-3/2*sin2x?y=sin^2x-3sinxcosx+4cos^2xy=sin^2x+cos^2x+3cos^2x-3/2*sin2x=1+3cos^2x-3/2*sin2x=1+3（1-sin^2x）-3/2*sin2x=-3sin^2x-3/2*sin2x+4 Y=sin^2x+sin2x+2cos^2x化简 y=3sin^2x-2sin2x+11cos^x的最大值 证明 2sin(π+x)cos(π-x)=sin2x 求y=(sin3x*sin^3x+cos3x*cos^3x)/cos^2x+sin2x最小值求y=(sin3x*sin³x+cos3x*cos³x)/cos²2x+sin2x最小值 求函数Y=sin^4x +cos^4x +sin^2x cos^2x 除以2-sin2x的最小正周期,最大值最小值 y=sin^2x+sin2x+2cos^x求函数的最小值 汗……不好意思，打错了是y==sin^2x+sin2x+2cos^2x 若x属于(0,π/2)则函数y=（2sin^2 x+cos^2 x）/sin2x的最小值为?分母为sin2x 不是sinx平方~ 化简：2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________ 化简：sin2x+sin(π-x)/2cos2x+2sin^2x+cos(-x)=? 已知函数y=sin^2x+sin2x+3cos^2x,求函数的最小值和单调减区间 求函数y=[sin2x+sin(2x+π/3)]/[cos2x +cos(2x+π/3)]的最小正周期 若函数y=cos^2 x - sin^2 x - √3sin2x+1求最大最小值.和最小周期