(x-y)^8÷(y-x)^4÷(x-y)^3要步骤
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 03:27:04
x){B8ہJ
́Xlҗ$铪EΆvUڢ+r) r5,tMt5!B@<;cmR}mq'ʽ9jЕ85*>K!Y kC$u
计算:[(x+y)³-2(x+y)²-4(x+y)]÷(x+y)
计算:(x-y)^8÷(y-x)^4×(x-y)
(x-y)^8÷(y-x)^4÷(x-y)^3要步骤
[x/(x-y)]·[y²/(x+y)]-[x^4y/(x^4-y^4)]÷[x²/(x²+y²)]=
[(x+2y)²-(x-2y)(x+2y)]÷4y
{(2x+y)2-y(y+4x)-8x}÷(2x)其中x=-2
【(2x+y)²-y(y+4x)-8x】÷2x,其中x=100
[(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y
[(x+2y)²-(x+y)(x-y)-7y²】÷(2y)
【(2x-y)(2x+y)+y(y-6x)】÷2x
4x-3y/x-2y÷6y-8x/y-2x
(x-y/x+y)^2÷(y-x/x^2+2xy+y^2)^2
1.(x^3-x^2-4x+1)/(x^2-3x+2)-(x^3-2x^2-9x+21)/(x^2-5x+6)+(x^2-3x+8)/(x^2-4x+3)2.{(x^2)/(x-y)}*{y/(x+y)}-{(x^4y)/(x^4-y^4)}÷{(x^2/x^2+y^2)^2}
(x²-4y²)÷(2x+y)/xy×1/x(2y-x)(2x+y)/xy 1/x(2y-x) 都是一项
已知x²+y²+6x-8x+25=0,求(x/x²-y² - 1/x+y)÷y/y-x
[(x+y)(x-y)-(x-y)²+2y(x-y)]÷(-2y)
[(x+2y)²-(x+y)(x-y)-4y²]÷2y
【2(x-y)³-8(x-y)²(x+y)+6y(x-y)²】÷2(x-y)²