斐波那契额数列# include int main(){int i = 1,j = 2,n,k = 0; printf ("请输入你要求的项数\n");scanf (" %d",&n); if (n==1)printf("您要求的和是1\n");else if (n==2)printf("您要求的和是2\n");else if(n>=3)for (;3

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