解下面三元一次方程组9x-5y+z=5 9x+y+4x=14 -9x+3y-5z=-11 3x-5y+2z=14x+5y-z=5x-5y+3z=-24x+3y-2z=-7 5x-6y+z=-2 2x+z=-2 5x-3y+6z=-3 2x-y+3z=0 y+3z=6 3x+2y 2x+y x-y+1 ----- - ---- = ----- 4 5 6

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