cos^2 x - 2sinxcosx - sin^2 x = 0 [ 0 ≤2x≤ pi ]cos^2 x - 2sinxcosx - sin^2 x = 0 [ 0 ≤2x≤ pi ]

cos^2+2sinxcosx+sin^2x 化简2*(sinxcosx-cos平方x)+1 化简 根号3sinXcosX+cos*2X y=sinxcosx+cos(2x)化简 化简:(cos*2x-0.5)/(sinxcosx) sin^2xtanx+(cos^2x/tanx)+2sinxcosx-1+cos/sinxcosx y=(cos^2x)/(sinxcosx-sin^2x),(0 sin²X-sinxcosx+2cos²x=化简 化简f(x)=cos^2(x+π/12)+sinxcosx sin²x+sinxcosx+2cos²x= 化简cos^4x-2sinxcosx-sin^4x 2sin平方x +cos平方x+3sinxcosx化简 求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx 证明1-2sinxcosx/cos^2x-sin^2x=cos^2x-sin^2/1+2sinxcosx 2sin^2x-sinxcosx-cos^2=1 化简y=2sinxcosx+2cos^2x-1 2sinxcosx-cos(2x-π/6)化简 化简1+2sinxcosx+2cos²x