函数f(x)=2lnx - x² - kx(k∈R),若函数f(x)存在两个零点m,n(0<m<n),且2x0=m+n.问:函数f(x)在点(x0,f(x0))处的切线能否平行于x轴?若能,求出该切线方程;若不能,说明理由.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/18 18:04:25
xT_oP*mMJPzC4M32e&-Sw<<==?sKI~VmӘ%FG#O>*Muj/ \VIXm1CMv]ScGޜtKJ K,siyoodѾϡKuG~3CS5L~oVÏf[^M%!*Z,}%/3pCܝnLNx)P(4=j.0v0m+$iqlp`@XDŚ$iGf5f(4Ak"BH(,
EVfX] GK&W{9W
(*F{%]TT:={,,"(e@ SI,EЖ#(L+n;b:V+,%}I
|B;:U
Dn>tRjޟʇw~onO=>bkQ~]7zX]RfypԼx &KcWWR)dk