已知数列an满足a1=1,且an=2an-1+2^n-1 ,an/2^n是等差数列我证好了,第二问是:求an前n项和Sn 可以有文字解释,适合学生看的,帮下学生~an/2^n是等差数列 且 d=1/2,a1=1/2 题意中的 an=2an-1+2^n-1 (n是正整数,n
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