已知数列an满足a1=1,且an=2an-1+2^n-1 ,an/2^n是等差数列我证好了,第二问是：求an前n项和Sn 可以有文字解释,适合学生看的,帮下学生~an/2^n是等差数列 且 d=1/2,a1=1/2 题意中的 an=2an-1+2^n-1 （n是正整数,n

已知数列{an}满足An+1=2^nAn,且A1=1,则通项an 已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an 已知数列{an}中满足(An+1-An)(An+1+An)=16,且a1=1,an 已知数列,an满足a1=1,a3+a7=18,且an-1+an+1=2an 已知数列an满足an+1/an=n+2/n且a1=1,则an= 已知数列{an}满足,an+2=an+1-an,且a10=-1,a9=0,求a1 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 已知数列｛an｝满足an=an+1 -lg2,且a1=1,则通项公式为? 已知数列{an}满足：an+1=an+n,且a61=2002,则a1等于 已知递增数列{an}满足a1=1,(2an+1)=an+(an+2),且a1,a2,a4成等比数列.求an 已知数列an满足:an+1-2an=2^n+1,且a1=2 (1)证明{an/2^n}是等差数列 (2)求数列an的 已知数列{an}满足:a1=1,且an-an-1=2n,求(1)a2,a3,a4.(2)求数列{an}的通项an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 已知数列{an}中a1=1,且满足an+an-1不等于0,Sn=1/6*(an+1)(an+2).(1)求通项an,并说明{an}是什么数列(2)求数列{an}的前n项和Sn 数列an满足,a1=8且8an+1an-16an+1+2an+5=0 已知数列{an}满足(n+1)an+1=an+n,且a1=2,则a2010=? 已知数列｛an｝满足a(n+1)=an+3n+2,且a1=2,求an=?