tan(-2010°)+cos(-79π/6)

tan(-2010°)+cos(-79π/6) sinπ+cos+(-π)+tanπ过程. 化简：sin²（α+π)cos(-α+π)/tan(α+π)tan(α+2π)cos²(-α-π)1.cos（27°+α）cos（33°-α）-sin（27°+α）sin（33°-α） 2.sin²（α+π)cos(-α+π)/tan(α+π)tan(α+2π)cos²(-α-π) 计算cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6[tan(-150°)cos（-210°）cos420°]/cot(-600°)sin（-1050°）cos25/6π+cos25/3π+tan(-25/4π)5sinπ/2+2cos0-3sin3/2π+10cosπtan10°t 计算（1）cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6[tan(-150°)cos（-210°）cos420°]/cot(-600°)sin（-1050°）cos25/6π+cos25/3π+tan(-25/4π)5sinπ/2+2cos0-3sin3/2π+10cosπt 化简：（1）sin（-α+180°）-tan(-α）+tan(-α+360°）/tan(α+180°）+cos(-α）+cos(α+180°）（2）sin^2(α+π）cos(-α+π）/tan(α+π）+tan(α+2π）cos^3(-α-π） tan(-150°)cos(-210°)cos(-420°)tan(-600°)/sin(-1050°) 计算 tan 30°+cos 30°/tan 45°-cos 60° 等于多少 cos^(50°+α)+cos^(40°-α)-tan(30°-α)*tan(60°+α) 计算 tan 30°+cos 30°/tan 45°-cos 60= Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2 求证cos（720°+α）（2/cosα+tanα）（1/cosα-2tanα）=2cosα-3tanα ①化简1+cos(π/2 +α)*sin(π/2 -α)*tan(π+α)②计算(1)tan(π/5)+tan(2π/5)+tan(3π/5)+tan(4π/5) (2)sin(-60°)+cos(225°)+tan135°(3)cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)（4）tan10°+tan170°+sin1866°-sin(-606°) 若α∈(0,π/6) 比较tan(sinα),tan(cosα),tan(tanα)的大小 【sin330°*tan(-13π/3)】/【cos(-19π/6)*cos690°】 [sin330°-tan(-13π/3）]/[cos(-19π/6）-cos690°] 求值sin17/6π,cos(-43π/6),tan(-1560°) sin(-1920°)=?cos(-1560°）=?tan(-17π/6）=?