正方形ABCD中,点G是AC上一点,GF⊥DG交BC的延长线于点F.(1)求证:GD=GF(我会证明)(2)延长FG交AB于点E,若∠BEG的平分线交DG的延长线于点交于H,EH交BC于点M,求证:CM+AE=2GH(3)在(2)的条件下,若
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