{x+y=60} {30%x+60%y=6}这个方程组的解
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x+x+x+y=60 .x-y=4
x+y=450;40%x+30=60%y
{x+y=450,60%y-40%x=30
3(x+y)+2(x-3y)=20,30%x+60%y=10%*60
请问60%x+20%y=30%(x+y) 怎么得到x:y=1:3
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
化简 x / y(x+y) - y / x(x+y) =
x+x+x-y-y=60 y+y+y-x-x=10 那么x=? y=?
x(x+y)(x-y)-y(y+x)(y-x)=(x-y)( )填空
x+x=y+30
{2x=y x/60+y/100=2.2
x+y=40 1.2x+1.6y=60
1000+y=60x 1000-y=40x
3x=y,x-10=y-60
X+Y=60 X:2Y=14:20
X+Y=60 X:2Y=14:20
60x+120y=360 x、y等于?
求解二元一次方程组120/(x+y) + 80/(x-y)=1630/(x+y) + 60/(x-y)=8120/(x+y) + 80/(x-y)=1630/(x+y) + 60/(x-y)=8