f(x)=2sin(wx-π/3)coswx+2cos(2wx+π/6),其中w>0.(1),若w=2,求函数f(x)的最小正周期?
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/11 10:29:13
xJ@_
ănM6[ITDAAO曰7#lW6la'\uY0z"o˷v;ozu,ꛧfq !GÎ>FX۱uY^fŴyrbN<cq0&Tb()AT+$¸>ahAL(N%R $QpP:t-:hY/&1
!1\ J(8\㙚RQz
f(x)=sin(2wx)+√3cos(2wx)怎么化成f(x)=sin(2wx+π/3)
请问f(x)=根号3sin(wx+φ)-cos(wx+φ)=2Sin(wx+φ-π/6)如何化简?
f(x)=4cos(wx-π/6)sinwx-cos(2wx+π/3)请化简
化简f(x)=2又根号3sin(wx/2)cos(wx/2)-2sin^2wx/2
已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0
已知函数f(x)=sin wx-cos wx最小周期为π 求w 若f(a/2)=1/3求sin2a的值
函数f(x)=√3sin^(wx/2)+sin(wx/2)cos(wx/2) (w>0)的周期为π,求w的值和函数f(x)的单调递增区间
[非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
求教:已知f(x)=根号3*sin(wx+a)-cos(wx+a) (0
f(x)=根号3sin(wx+q)-cos(wx+q),(w>0,0
已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0
已知函数f(x)=根号3sin(wx+a)-cos(wx+a)(0
已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0
已知函数f(x)=根号3sin(wx+fai)-cos(wx+fai)(0
已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0
已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0