1.化简:|x-1|+|6x-1|2.若a,b,c为任意的三个整数,则1/2(a+b),1/2(c+b),1/2(a+c)中,整数的个数有____个.3.设n为奇数,试证明:n的二次方-1能被8整除(格式要完整)4.求证:一个三位数的各数字之和是9的倍数,则这
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求余数1.(x平方-2x+3)除以(2x+3)2.(x五次方-1)除以(x-2)3.21x五次+33x四次-70x三次+21x平方+x-1)除以x分解因式2x三次+5x平方2x-94x三次-15x平方+8x+3x四次-5x三次+20x-16x四次-2x平方+3x-2x五次-10x平方+15x-6若有若(
1.x平方-1分之x平方+x 2.x平方-6x+9分之x平方-9 化简
几道初中数学题..要有过程 注:x^2 表示x的2次方1.化简:(9x^2+3x)/(x^2+6x+9) * (x^3+27)/(x^2-3x) ÷ (x^2-3x+9)/(x^2-9)2.化简x - x÷{(x^2-y^2)/(x^3+y^3) * [(x-(x^2+y^2)/y ) ÷ (1/x - 1/y)3.化简分式: (x^3 + 5x^2 + 3x - 9)/(x^3
化简|X+6|+|X-4| |X-2|-|X+3|-|X-4|大神们帮帮忙1.化简 |X+6|+|X-4| |X-2|-|X+3|-|X-4| 2.求当|X-6|+|X+3|+|X+5|有极小值时X的值 3.求当X为何值时|X+1|-|X+6|的值为0
1.若x>5时,化简|x-5|-|2x-13| 2.|3x-2|+|2x+3| 3.||x-1|-3|+|3x+1|
帮帮忙做下了: 1.化简(x+y)×x^2/(x^2-y^2)+1/(x-y)-(2x^2y-2xy^2)/(x^2-2xy+y^2)2.(x^2-9)/(x^2+5x+6)-(x^2-x-2)/(x^2-2x)+(x^2+2x+4)(x^3-8)
1.【x-1分之x平方+3x+2】+【6分之2+x-x平方】-【10-x分之4-x平方】2.【x+1-1分之1-x】除以【x-x平方分之x-1】3.【x平方-4分之x平方-x-6】+【x+2分之x-3】这个结果再除以【x+1分之x-3】4.【x分之x-y】乘以
1.(x^3-x^2-4x+1)/(x^2-3x+2)-(x^3-2x^2-9x+21)/(x^2-5x+6)+(x^2-3x+8)/(x^2-4x+3)2.{(x^2)/(x-y)}*{y/(x+y)}-{(x^4y)/(x^4-y^4)}÷{(x^2/x^2+y^2)^2}
1.若X+X/1=6,求X²+X²/1的值 2.已知X²-6X+1=0,求X²+X²/1的值 3.已知X²+X+
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x
1.若x分之(x+1)=5,求(x的四次方-x的平方+1)分之(x的四次方+x的平方+1)的值.(详见内2.化简 x(x+1)分之一 + (x+1)(x+3)分之2 + (x+3)(x+6)分之3
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
1.(x*2-3x+3)/(x*2-3x+2)-(x*2-5x+7)/(x*2-5x+6)-1/(x*2-4x+3)2.1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6) 3.已知:x*2-3x+1=0,求x*2+1/x*2.
1.x/x-y * y^2/x+y -x^4y/x^4-y^4÷ x^2/x^2+y^2 2.(x^2-4/x^2-x-6+ x+2/x-3)÷ x+1/x-33.(x+1-1/1-x)÷(x- x^2/x-1)4.x-1/x^2+3x+2/6/2+x-x^2-10-x/4-x^21111111111111111111111111111111
1.用公式计算:COSX=1-X*X/2!X*X*X*X/4!-X*X*X*X*X*X/6!.直到最后一项的绝对
1.已知:x+y=0.2,x+3y=1,求3x^2+12xy+12y^2的值.2.化简:(1) (x^2-6x+9)/(x^2-4)(2) (x^2-4x)/(x^2-8x+16)3.解方程:(1) 1/(x-4)=4/(x^2-16)(2) 3/(x-1)-(x+2)/[x(x-1)]=0(3) (2-x)/(x-3)+1/(3-x)=1如果过程写得好,
因式分解 1.x^6-y^6-2x^3+1 2.x^4+64 3.(x-3)(x-1)(x+2)(x+4)+24 4.(6x-1)(2x-1)(3x-1)(x-1)+x^2