x+1/3-y+2/4=0 x-3/4-y-3/3=1/12 二元一次方程 x+1/3-y+2/4=0 x-3/4-y-3/3=1/12 二元一次方程

若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 {4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 先化简再求值; 解方程组 x(x-y)-y(x+y)+2xy 其中x=2 ,y=-22.x[x-x(x-1)],其中x=-2解方程组4x+3y=12x-y=32.y+1=2x 4x-y=2 3.2x+2y=0 2x-y+24=0 x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=? x²-4x-1=0,求(2x-3)²-(x+y)(x-y)-y² (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= 解下列方程组：{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 3x+4y-5=0 x^2+y^2=1求x.y 先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 9y=3x-(x-1),4(x+y)-(2x+4)=8y 已知实数x、y满足|2x-y+1|+3根号3x-2y+4=0,求代数式[(x-y)/(x-2y)]/(x的平方-2y)/[(x的平方-y的平方）/x的已知实数x、y满足|2x-y+1|+3根号3x-2y+4=0,求代数式[(x-y)/(x-2y)]/(x的平方-2y)/[(x的平方-y的平方）/（x的 4x(x-y)-(2x-3y)(2x-3y) x=1 y=-1