在△ABC中,∠A=50°,∠B,∠C的角平分线相交于点O,则∠BOC的读数为(此题无图)①∠3=1/2∠ABC,∠4=∠ACB,在△BOC中,∠BOC=180°-(∠3+∠4)=180°-1/2(∠ABC+∠ACB)=180°-1/2(180°-∠A)=90°+1/2∠A=90°+25°=115°

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