2【a-1】²-12【a-1】+18 【x²-2xy+y²】+【-2x+2y】+1a²-8ab+16b²x+y=0.2,x+3y=1 求3x²+12xy+12y²的值1.2【a-1】²-12【a-1】+18 2.【x²-2xy+y²】+【-2x+2y】+13.a²-8ab+16b²4.x+y=0.x+3
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