2^m=5,2^n=6.求2^(2m-n+1)

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2^m=5,2^n=6.求2^(2m-n+1)
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2^m=5,2^n=6.求2^(2m-n+1)
2^m=5,2^n=6.求2^(2m-n+1)

2^m=5,2^n=6.求2^(2m-n+1)
2^(2m-n+1)=2^(2m)÷2^n×2
=(2^m)²÷2^n×2
=25÷6×2
=25/3

2^(2m-n+1)

m=lg5/lg2 n=lg6/lg2
2m-n+1=(2lg5-lg6)/lg2 + lg2/lg2=log2 25/3
原式=25/3