10^a=2,10^b=3,则100^[(3a/2)-(b/3)]=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/12/03 00:30:30
10^a=2,10^b=3,则100^[(3a/2)-(b/3)]=?
x)34K5RI:O;fEk'ij$k$RΆ4S%lڪPkƉFU@% ,`W3XH@"pe!i_\gr3WD6

10^a=2,10^b=3,则100^[(3a/2)-(b/3)]=?
10^a=2,10^b=3,则100^[(3a/2)-(b/3)]=?

10^a=2,10^b=3,则100^[(3a/2)-(b/3)]=?
100^[(3a/2)-(b/3)] =10^{2[(3a/2)-(b/3)]} =10^[3a-(2b/3)] =10^(3a)/10^(2b/3) =(10^a)^3/(10^b)^(2/3) =2^3/(3)^(2/3) =8/9^(1/3)