已知圆(x-3)^2+(y+5)^2=36和点A(2,2)B(-1,-2),若点C在圆上且△ABC的面积为5/2,则满足条件的点C的个数是
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已知圆(x-3)^2+(y+5)^2=36和点A(2,2)B(-1,-2),若点C在圆上且△ABC的面积为5/2,则满足条件的点C的个数是
已知圆(x-3)^2+(y+5)^2=36和点A(2,2)B(-1,-2),若点C在圆上且△ABC的面积为5/2,则满足条件的点C的个数是
已知圆(x-3)^2+(y+5)^2=36和点A(2,2)B(-1,-2),若点C在圆上且△ABC的面积为5/2,则满足条件的点C的个数是
|AB|=5
所以三角形高=1
即C到AB距离是1
AB是4x-3y-2=0
圆心到AB距离=|12+15-2|/5=5
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