作业帮9(x+1)²(x-1)²-6(x²-1)y+y²
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 05:27:31
x)Ԩ6TS64֨Ѕ1u4*,CJJ&HD v6lvXO? ,cka= @1tA
!PMUV@6&
ӤWW1ne-
4麞+lΧki_\g
Cz(@F:V,m0]
03ZQ,cMlV)*afYOO7yӍSi jv`BU& 351VSC)^lݎ$ iI-u
9(x+1)²(x-1)²-6(x²-1)y+y²
9(x+1)²(x-1)²-6(x²-1)y+y²
9(x+1)²(x-1)²-6(x²-1)y+y²
是要分解因式吧
=9【（x+1）（x-1）】² -6(x²-1)y + y²
=9（x²-1）² - 6(x²-1)y + y²
={3(x²-1)-y}²（完全平方公式）
9(x+1)²(x-1)²-6(x²-1)y+y²
=[3(x²-1)] ²-6(x²-1)y+y²
=[3(x²-1) ²- y] ²
=【[(√3) (x²-1)] ²- (√y) ²】²...
全部展开
9(x+1)²(x-1)²-6(x²-1)y+y²
=[3(x²-1)] ²-6(x²-1)y+y²
=[3(x²-1) ²- y] ²
=【[(√3) (x²-1)] ²- (√y) ²】²
=[(√3) (x²-1) + (√y)] [(√3) (x²-1) - (√y)]
=[(√3) (x+1)(x-1) + (√y)] [(√3) (x+1)(x-1) - (√y)]
收起