①已知x²-7xy+12y²=0,x,y均不为0,求x+y/x-y的值
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①已知x²-7xy+12y²=0,x,y均不为0,求x+y/x-y的值
①已知x²-7xy+12y²=0,x,y均不为0,求x+y/x-y的值
①已知x²-7xy+12y²=0,x,y均不为0,求x+y/x-y的值
由题意得(x-3y)(x-4y)=0 ∴x=3y或x=4y
∴x+y/x-y=4y/2y=2或x+y/x-y=5y/3y=5/3
即x+y/x-y=2或5/3
x^2-7xy+12y^2=0
因式分解得(x-3y)(x-4y)=0
因此有x=3y或x=4y
带入得2或5/3
x²-7xy+12y²=(x-4y)(x-3y)=0
x=3y或4y,
(x+y)/(x-y)=2或 5/3