lim(x趋向于0)(1-cosx)/x^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 01:39:46
x)}Ŷ&>g~O'PP79BS"&Hev6DIO[<~,QtqfFf,Tݳr@ӟXsBEp)kÔiꛠ)37¢
(i_\g
$t
lim(x趋向于0)(1-cosx)/x^2
lim(x趋向于0)(1-cosx)/x^2
lim(x趋向于0)(1-cosx)/x^2
倍角公式:cosx=1-2[sin(x/2)]^2
故1-cosx=2[sin(x/2)]^2
于是
lim x->0 (1-cosx)/x^2
=lim x->0 2[sin(x/2)]^2/x^2
=lim x->0 2[(sin(x/2)/(x/2)]^2*1/4
=lim x->0 1/2*[(sin(x/2)/(x/2)]^2
=1/2
lim(x趋向于0)(1-cosx)/x^2
lim(cosx)^(1/(1-cosx)).x趋向于0
大数lim(cosx)^(1/(1-cosx)).x趋向于0
lim极限趋向于0+求x/√(1-cosx)
lim(1-cosx)/x2 x趋向于0
1-√cosx/xsinx 求Lim X趋向于0
lim(x趋向于0)(cosx)^[1/(xsinx)]=
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
lim(x趋向于0)(1-cosx^2)/((x^3)*sinx)
lim(1-cosx)x趋向0,
1.lim(sinx)^2/√(1+xsinx)-√cosx x趋向于02. lim(cos√x)^cotx x趋向于0 3.lim(1-x)tanπx/2 x趋向于0+ 求各位大神帮个忙1.lim(sinx)^2/√{(1+xsinx)-√cosx} x趋向于0额,第一题式子应该是这样的
lim X趋向于0 cosx等于多少为什么?
1.x趋向0 lim (cosx-1)/x 2.x趋向0 lim sinx/x
x趋向于0,lim[x*ln(1+3x)]/(1-cosx)
极限lim(x-sinx)/[x(1-cosx)] 其中x趋向于0
(x趋向于0)lim(cosx-cos2x)/x^2
求极限lim[1-(cosx)^0.5]/[1-cos(x)^0.5] 其中x趋向于0正
求极限 lim(x趋向于0) (cosx)^(1/x^2)