解方程组x/4=y/3=z/5 x-y-z=4a(a是常数)

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解方程组x/4=y/3=z/5 x-y-z=4a(a是常数)
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解方程组x/4=y/3=z/5 x-y-z=4a(a是常数)
解方程组x/4=y/3=z/5 x-y-z=4a(a是常数)

解方程组x/4=y/3=z/5 x-y-z=4a(a是常数)
解析,
设x/4=y/3=z/5=t
那么,x=4t,y=3t,z=5t
故,4t-3t-5t=4a,t=-a
因此,x=-4a,y=-3a,z=-5a

令x/4=y/3=z/5=k
x=4k
y=3k
z=5k
x-y-z=4a
4k-3k-5k=4a
4k=-4a
k=-a
x=4k=4*(-a)=-4a
y=3k=3*(-a)=-3a
z=5k=5*(-a)=-5a