k/(k+1)+1/(k+1)(k+2) =1-1/(k+1)+1/(k+1)-1/(k+2) =1-1/(k+2) =(k+1)/(k+2)k/(k+1)+1/(k+1)(k+2)……………………(1)=1-1/(k+1)+1/(k+1)-1/(k+2)…………(2)=1-1/(k+2)……………………………(3)=(k+1)/(k+2)…………………
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k/(k+1)+1/(k+1)(k+2) =1-1/(k+1)+1/(k+1)-1/(k+2) =1-1/(k+2) =(k+1)/(k+2)k/(k+1)+1/(k+1)(k+2)……………………(1)=1-1/(k+1)+1/(k+1)-1/(k+2)…………(2)=1-1/(k+2)……………………………(3)=(k+1)/(k+2)…………………
k/(k+1)+1/(k+1)(k+2) =1-1/(k+1)+1/(k+1)-1/(k+2) =1-1/(k+2) =(k+1)/(k+2)
k/(k+1)+1/(k+1)(k+2)……………………(1)
=1-1/(k+1)+1/(k+1)-1/(k+2)…………(2)
=1-1/(k+2)……………………………(3)
=(k+1)/(k+2)…………………………(4)
第(1)步是怎样得到第(2)步的啊
k/(k+1)+1/(k+1)(k+2) =1-1/(k+1)+1/(k+1)-1/(k+2) =1-1/(k+2) =(k+1)/(k+2)k/(k+1)+1/(k+1)(k+2)……………………(1)=1-1/(k+1)+1/(k+1)-1/(k+2)…………(2)=1-1/(k+2)……………………………(3)=(k+1)/(k+2)…………………
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