如图,一条直线上有三点A、B、C,点C在点A与点B之间,点P是此直线外一点,设∠APC=α,∠BPC=β.求证:sin(α+β)/PC=(sinα/PB)+(sinβ/PA)
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![如图,一条直线上有三点A、B、C,点C在点A与点B之间,点P是此直线外一点,设∠APC=α,∠BPC=β.求证:sin(α+β)/PC=(sinα/PB)+(sinβ/PA)](/uploads/image/z/10072768-40-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E4%B8%80%E6%9D%A1%E7%9B%B4%E7%BA%BF%E4%B8%8A%E6%9C%89%E4%B8%89%E7%82%B9A%E3%80%81B%E3%80%81C%2C%E7%82%B9C%E5%9C%A8%E7%82%B9A%E4%B8%8E%E7%82%B9B%E4%B9%8B%E9%97%B4%2C%E7%82%B9P%E6%98%AF%E6%AD%A4%E7%9B%B4%E7%BA%BF%E5%A4%96%E4%B8%80%E7%82%B9%2C%E8%AE%BE%E2%88%A0APC%3D%CE%B1%2C%E2%88%A0BPC%3D%CE%B2.%E6%B1%82%E8%AF%81%EF%BC%9Asin%28%CE%B1%2B%CE%B2%29%2FPC%3D%28sin%CE%B1%2FPB%29%2B%28sin%CE%B2%2FPA%29)
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