已知实数a,b分别满足a2-6a+4=0,b2-6b+4=0且a不等于b,则b/a+a/b的值是多 少?谢谢.
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![已知实数a,b分别满足a2-6a+4=0,b2-6b+4=0且a不等于b,则b/a+a/b的值是多 少?谢谢.](/uploads/image/z/1011347-35-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0a%2Cb%E5%88%86%E5%88%AB%E6%BB%A1%E8%B6%B3a2-6a%2B4%3D0%2Cb2-6b%2B4%3D0%E4%B8%94a%E4%B8%8D%E7%AD%89%E4%BA%8Eb%2C%E5%88%99b%2Fa%2Ba%2Fb%E7%9A%84%E5%80%BC%E6%98%AF%E5%A4%9A+%E5%B0%91%3F%E8%B0%A2%E8%B0%A2.)
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已知实数a,b分别满足a2-6a+4=0,b2-6b+4=0且a不等于b,则b/a+a/b的值是多 少?谢谢.
已知实数a,b分别满足a2-6a+4=0,b2-6b+4=0且a不等于b,则b/a+a/b的值是多 少?谢谢.
已知实数a,b分别满足a2-6a+4=0,b2-6b+4=0且a不等于b,则b/a+a/b的值是多 少?谢谢.
∵满足a^2-6a+4=0,b^2-6b+4=0
∴a、b为方程x^2-6x+4的两个解
通分x2/x1+x1/x2得 (x1+x2)^2-2x1·x2/x1`x2
∵x1+x2=-b/a,x1·x2=c/a
∴x1+x2=6,x1·x2=4
代入原式=28/4=7
∴选择A
答案:7
∵满足a^2-6a+4=0,b^2-6b+4=0
∴a、b为方程x^2-6x+4的两个解
通分x2/x1+x1/x2得 (x1+x2)^2-2x1·x2/x1`x2
∵x1+x2=-b/a,x1·x2=c/a
∴x1+x2=6,x1·x2=4
代入原式=28/4=7
望采纳为满意答案
谢谢!