已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
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![已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值](/uploads/image/z/10119068-44-8.jpg?t=%E5%B7%B2%E7%9F%A5cos%283%CF%80%2F2-%CE%B1%29%3D1%2F3%2Csin9%CE%B1%2B%CE%B2%29%3D1.%E6%B1%82cos%282%CE%B1%2B%CE%B2%29%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5cos%283%CF%80%2F2+-%CE%B1%29%3D1%2F3%2Csin%EF%BC%88%CE%B1%2B%CE%B2%29%3D1.%E6%B1%82cos%282%CE%B1%2B%CE%B2%29%E7%9A%84%E5%80%BC)
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已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值
已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
cos(3π/2 -α)=1/3
-sina= 1/3
sina= -1/3
sin(α+β)=1
可得cos(α+β)=0
cos(2α+β)=cosa*cos(α+β)-sinasin(α+β)= 1/3