已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/23 20:35:47
已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
x){}K57ۨikoSgynM@޳M FZ6AӨzmɷnҬ/Hcj '*.pH o:4=p+ىZ l C @!

已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值
已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值

已知cos(3π/2-α)=1/3,sin9α+β)=1.求cos(2α+β)的值已知cos(3π/2 -α)=1/3,sin(α+β)=1.求cos(2α+β)的值
cos(3π/2 -α)=1/3
-sina= 1/3
sina= -1/3
sin(α+β)=1
可得cos(α+β)=0
cos(2α+β)=cosa*cos(α+β)-sinasin(α+β)= 1/3