(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少

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(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少
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(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少
(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少

(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少
令a=x²+y²
则a²-a=12
a²-a-12=0
(a-4)(a+3)=0
a=4,a=-3
平方数大于等于0
所以a=-3不成立
所以x²+y²=a=4

令t=x*x+y*y，t>0
原方程即为
t*t-t=12
t*t-t-12=0
(t-4)(t+3)=0
t=4或-3（舍）
所一x*x+y*y=4

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