作业帮1/sin10°-2sin70°+sin[arccos(-根号3/2)]
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1/sin10°-2sin70°+sin[arccos(-根号3/2)]
1/sin10°-2sin70°+sin[arccos(-根号3/2)]
1/sin10°-2sin70°+sin[arccos(-根号3/2)]
楼主解出来了?怎么解的?
1/sin10°应该是1/2sin10°
arccos函数的定义域是（-1,1）楼主题有问题吧
1/sin10°-2sin70°+sin[arccos(-根号3/2)]
求值2sin20°+2cos20°+cos70°sin10°/sin70°
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sin10°sin30°sin50°sin70°=?
sin10°sin30°sin50°sin70°=?
sin10°*sin30°*sin50°*sin70° 怎么做?
sin10°sin30°sin50°sin70°=?
sin10°*sin30°*sin50°*sin70°等于多少?
cos70°cos10°+sin70°sin10°的值,
求值：sin10°sin50°sin70°sin80°
sin20°sin10°-cos10°sin70°等于多少?
sin20°sin10°-cos10°sin70°
化简：sin10°sin50°sin60°sin70°
sin10°×sin50°×sin70°等于多少
sin10°*sin50°*sin70°等于好多
求值：sin10°sin50°·sin70°
sin10°sin50°sin70° 怎样化简求值?
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