已知过定点P(0,1)的直线l交双曲线x^2-y^2/4=1于A,B两点,问:若直线AB的中点为M,求M点的轨迹方程答案是4x^2-y^2+y=0(y1).我就是想问下,y的范围怎么出来的.还有为什么不能取等号.
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![已知过定点P(0,1)的直线l交双曲线x^2-y^2/4=1于A,B两点,问:若直线AB的中点为M,求M点的轨迹方程答案是4x^2-y^2+y=0(y1).我就是想问下,y的范围怎么出来的.还有为什么不能取等号.](/uploads/image/z/10137678-6-8.jpg?t=%E5%B7%B2%E7%9F%A5%E8%BF%87%E5%AE%9A%E7%82%B9P%280%2C1%29%E7%9A%84%E7%9B%B4%E7%BA%BFl%E4%BA%A4%E5%8F%8C%E6%9B%B2%E7%BA%BFx%5E2-y%5E2%2F4%3D1%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E9%97%AE%EF%BC%9A%E8%8B%A5%E7%9B%B4%E7%BA%BFAB%E7%9A%84%E4%B8%AD%E7%82%B9%E4%B8%BAM%2C%E6%B1%82M%E7%82%B9%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%E7%AD%94%E6%A1%88%E6%98%AF4x%5E2-y%5E2%2By%3D0%28y1%29.%E6%88%91%E5%B0%B1%E6%98%AF%E6%83%B3%E9%97%AE%E4%B8%8B%2Cy%E7%9A%84%E8%8C%83%E5%9B%B4%E6%80%8E%E4%B9%88%E5%87%BA%E6%9D%A5%E7%9A%84.%E8%BF%98%E6%9C%89%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%8D%E8%83%BD%E5%8F%96%E7%AD%89%E5%8F%B7.)
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