z=x+y 2x-3y+2z=5 x+2y-z=3 这个方程怎么解?
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z=x+y 2x-3y+2z=5 x+2y-z=3 这个方程怎么解?
z=x+y 2x-3y+2z=5 x+2y-z=3 这个方程怎么解?
z=x+y 2x-3y+2z=5 x+2y-z=3 这个方程怎么解?
将z=x+y 代入后面两式中,所以4X-Y=5,Y=3,所以X=2 ,Z=5
三个方程变形得到:
x+y-z=0...(1)
2x-3y+2z=5...(2)
x+2y-z=3...(3)
(1)-(3)得到:
y=3....(4)
(2)-(3)*2得到:
-7y+4z=-1...(5)
由(4)、(5)得到:
y=3,z=5.
进而代入(1)得到:x=2.
x/2=y/3=z/5 x+3y-z/x-3y+z
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