(x2-x)^2-(x-1)^2
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![(x2-x)^2-(x-1)^2](/uploads/image/z/10144580-68-0.jpg?t=%28x2-x%29%5E2-%28x-1%29%5E2)
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(x2-x)^2-(x-1)^2
(x2-x)^2-(x-1)^2
(x2-x)^2-(x-1)^2
(x2-x)^2-(x-1)^2
=(x2-x+x-1)(x2-x-x+1)
=(x2-1)(x2-2x+1)
=(x+1)(x-1)(x-1)^2
=(x-1)^3(x+1)
(x2-x)^2-(x-1)^2
=(x^2-x+x-1)(x^2-x-x+1)
=(x^2-1)(x^2-2x+1)
=(x+1)(x-1)(x-1)^2
=(x+1)(x-1)^3
化简x/x2+x除以x2+x-2/x2-1+x+1/x+2
计算(x3+x2+x+2)/(x2+1)
3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x
通分 3x/x2-2x,2x+1/4-x2,3/2x2+4x
化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1
(x2-3x)2-x(x2-3x)-2x2
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
因式分解 (x2+2x)2+2x2+4x+1
x2+(x+1)2+x2(x+1)2因式分解
x2+(1+x)2+(x+x2)2因式分解,
2( x2 +1/x2) - 9( x + 1/x) + 14 =
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
因式分解(x2+x+1)(x2+x+2)-12=
证明:根号(x2+2x+4)-根号(x2-x+1)
解方程(x2+x)(x2+x-2)=-1
y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)x2为的平方
约分x2+x-2/x2-x-6