1)解关于x的方程:x^2+3bx-a^2+ab+2b^2=02) (√a+1 + √a-1)/(√a+1 - √a-1)3 2(x+1)-√24)已知△ABC的三边为a b c且关于x的一元二次方程x^2+2(b-c)x=(b-c)(a-b)有两个相等的实数根,请判别该三角形的形状。
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/02 06:36:31
![1)解关于x的方程:x^2+3bx-a^2+ab+2b^2=02) (√a+1 + √a-1)/(√a+1 - √a-1)3 2(x+1)-√24)已知△ABC的三边为a b c且关于x的一元二次方程x^2+2(b-c)x=(b-c)(a-b)有两个相等的实数根,请判别该三角形的形状。](/uploads/image/z/10151150-14-0.jpg?t=1%EF%BC%89%E8%A7%A3%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8B%EF%BC%9Ax%5E2%2B3bx-a%5E2%2Bab%2B2b%5E2%3D02%29+%28%E2%88%9Aa%2B1+%2B+%E2%88%9Aa-1%29%2F%28%E2%88%9Aa%2B1+-+%E2%88%9Aa-1%293+2%28x%2B1%29-%E2%88%9A24%EF%BC%89%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9%E4%B8%BAa+b+c%E4%B8%94%E5%85%B3%E4%BA%8Ex%E7%9A%84%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%5E2%2B2%28b-c%29x%3D%EF%BC%88b-c%29%28a-b%29%E6%9C%89%E4%B8%A4%E4%B8%AA%E7%9B%B8%E7%AD%89%E7%9A%84%E5%AE%9E%E6%95%B0%E6%A0%B9%EF%BC%8C%E8%AF%B7%E5%88%A4%E5%88%AB%E8%AF%A5%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%BD%A2%E7%8A%B6%E3%80%82)
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