三角形ABC中 AB=AC 角ABC=2角A ,BM平分角ABC交于外接圆于点M ME平行BC交于点E 判断四边形EBCM的形状 并证
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![三角形ABC中 AB=AC 角ABC=2角A ,BM平分角ABC交于外接圆于点M ME平行BC交于点E 判断四边形EBCM的形状 并证](/uploads/image/z/10158398-62-8.jpg?t=%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD+AB%3DAC+%E8%A7%92ABC%3D2%E8%A7%92A+%2CBM%E5%B9%B3%E5%88%86%E8%A7%92ABC%E4%BA%A4%E4%BA%8E%E5%A4%96%E6%8E%A5%E5%9C%86%E4%BA%8E%E7%82%B9M+ME%E5%B9%B3%E8%A1%8CBC%E4%BA%A4%E4%BA%8E%E7%82%B9E+%E5%88%A4%E6%96%AD%E5%9B%9B%E8%BE%B9%E5%BD%A2EBCM%E7%9A%84%E5%BD%A2%E7%8A%B6+%E5%B9%B6%E8%AF%81)
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