已知向量a=(2,cosx),向量b=(sin(x+π/6),-2),f(x)=向量a*向量b(x属于R).求函数f(x)单调增区间;若f(x)=6/5,求cos(2x-π/3的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/06 15:58:42
![已知向量a=(2,cosx),向量b=(sin(x+π/6),-2),f(x)=向量a*向量b(x属于R).求函数f(x)单调增区间;若f(x)=6/5,求cos(2x-π/3的值](/uploads/image/z/10162332-36-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa%3D%282%2Ccosx%29%2C%E5%90%91%E9%87%8Fb%3D%28sin%28x%2B%CF%80%2F6%29%2C-2%29%2Cf%28x%29%3D%E5%90%91%E9%87%8Fa%2A%E5%90%91%E9%87%8Fb%EF%BC%88x%E5%B1%9E%E4%BA%8ER%EF%BC%89.%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4%EF%BC%9B%E8%8B%A5f%28x%29%3D6%2F5%2C%E6%B1%82cos%282x-%CF%80%2F3%E7%9A%84%E5%80%BC)
x͑J@_''n<[QhAf1ZҍhF_PIW0"sfގbںD֞EeT
]vmLmܒBd-QY̥
?5N $,A69!x|uv:!-D9Ujʹ>Dogæۣ Ԛ+^6D0w>1,PT)\U"S3]K S-
Ae{pb
KrX~=|!TJ(+JݻIULv(iY<
已知向量a=(2,cosx),向量b=(sin(x+π/6),-2),f(x)=向量a*向量b(x属于R).求函数f(x)单调增区间;若f(x)=6/5,求cos(2x-π/3的值
已知向量a=(2,cosx),向量b=(sin(x+π/6),-2),f(x)=向量a*向量b(x属于R).
求函数f(x)单调增区间;若f(x)=6/5,求cos(2x-π/3的值
已知向量a=(2,cosx),向量b=(sin(x+π/6),-2),f(x)=向量a*向量b(x属于R).求函数f(x)单调增区间;若f(x)=6/5,求cos(2x-π/3的值
f(x)=2sin(x+π/6)-2cosx和角公式展开,化简得:
f(x)=√3sinx-cosx=2sin(x-π/6)
x-π/6∈[-π/2+2kπ,π/2+2kπ]
解出x即是增区间.
2sin(x-π/6)=6/5
sin(x-π/6)=3/5
cos(2x-π/3)=1-2sin(x-π/6)^2=7/25