求(x-2y)²-4(2x-y)²=?16(x+y)²-25(x-y)²=?a的2n+1次方-16a的2n-1次方
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![求(x-2y)²-4(2x-y)²=?16(x+y)²-25(x-y)²=?a的2n+1次方-16a的2n-1次方](/uploads/image/z/1017175-31-5.jpg?t=%E6%B1%82%EF%BC%88x-2y%EF%BC%89%26%23178%3B-4%EF%BC%882x-y%EF%BC%89%26%23178%3B%3D%3F16%EF%BC%88x%2By%29%26%23178%3B-25%EF%BC%88x-y%29%26%23178%3B%3D%3Fa%E7%9A%842n%2B1%E6%AC%A1%E6%96%B9-16a%E7%9A%842n-1%E6%AC%A1%E6%96%B9)
求(x-2y)²-4(2x-y)²=?16(x+y)²-25(x-y)²=?a的2n+1次方-16a的2n-1次方
求(x-2y)²-4(2x-y)²=?16(x+y)²-25(x-y)²=?a的2n+1次方-16a的2n-1次方
求(x-2y)²-4(2x-y)²=?16(x+y)²-25(x-y)²=?a的2n+1次方-16a的2n-1次方
(x-2y)²-4(2x-y)²
=(x-2y+2(2x-y))(x-2y-2(2x-y))
=(5x-4y)(-3x)
=-3x(5x-4y)
16(x+y)²-25(x-y)²
=(4(x+y)+5(x-y))(4(x+y)-5(x-y))
=(9x-y)(-x+9y)
a的2n+1次方-16a的2n-1次方
=a^(2n-1)(a^2-16)
=a^(2n-1)(a+4)(a-4)
(x-2y)²-4(2x-y)²
=[x-2y-2((2x-y)][x-2y+2(2x-y)]
=(x-2y-4x+2y)(x-2y+4x-2y)
=-3x(5x-4y)
16(x+y)²-25(x-y)²
=[4(x+y)-5(x-y)][4(x+y)+5(x-y)]
=(4x+4y-5x+5y)(4x+4y...
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(x-2y)²-4(2x-y)²
=[x-2y-2((2x-y)][x-2y+2(2x-y)]
=(x-2y-4x+2y)(x-2y+4x-2y)
=-3x(5x-4y)
16(x+y)²-25(x-y)²
=[4(x+y)-5(x-y)][4(x+y)+5(x-y)]
=(4x+4y-5x+5y)(4x+4y+5x-5y)
=(9y-x)(9x-y)
a的2n+1次方-16a的2n-1次方
=a的2n-1次方(a²-16)
=a的2n-1次方(a-4)(a+4)
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