函数 f(x)=(x-1)(x-2)(x-3)...(x-2007) 则f'(2007)=?

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函数 f(x)=(x-1)(x-2)(x-3)...(x-2007) 则f'(2007)=?
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函数 f(x)=(x-1)(x-2)(x-3)...(x-2007) 则f'(2007)=?
函数 f(x)=(x-1)(x-2)(x-3)...(x-2007) 则f'(2007)=?

函数 f(x)=(x-1)(x-2)(x-3)...(x-2007) 则f'(2007)=?
f'(x)=
(x-2)(x-3)...(x-2007)[少个x-1]
+(x-1)(x-3)(x-4)...(x-2007)[少个x-2]
+...
+(x-1)(x-2)(x-3)...(x-2006)[少个x-2007]
所以f'(2007)=0+0+...+0+2006*2005*...*1=2006!