Matlab 正态分布 已知 Matlab 程序 得出Xf 和 Yf的位移 ,如下:Clearl=1;T=linspace(0,60,3000);fa=T.*10*pi/60xf=-0.5*l.*sin(fa); % velocity in the direction of xfyf=0.5*l.*cos(fa)-1.5*l; % velocity in the direction of yffor n=1:3000theta2
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![Matlab 正态分布 已知 Matlab 程序 得出Xf 和 Yf的位移 ,如下:Clearl=1;T=linspace(0,60,3000);fa=T.*10*pi/60xf=-0.5*l.*sin(fa); % velocity in the direction of xfyf=0.5*l.*cos(fa)-1.5*l; % velocity in the direction of yffor n=1:3000theta2](/uploads/image/z/10199122-34-2.jpg?t=Matlab+%E6%AD%A3%E6%80%81%E5%88%86%E5%B8%83+%E5%B7%B2%E7%9F%A5+Matlab+%E7%A8%8B%E5%BA%8F+%E5%BE%97%E5%87%BAXf+%E5%92%8C+Yf%E7%9A%84%E4%BD%8D%E7%A7%BB+%2C%E5%A6%82%E4%B8%8B%EF%BC%9AClearl%3D1%3BT%3Dlinspace%280%2C60%2C3000%29%3Bfa%3DT.%2A10%2Api%2F60xf%3D-0.5%2Al.%2Asin%28fa%29%3B+%25+velocity+in+the+direction+of+xfyf%3D0.5%2Al.%2Acos%28fa%29-1.5%2Al%3B+%25+velocity+in+the+direction+of+yffor+n%3D1%3A3000theta2)
Matlab 正态分布 已知 Matlab 程序 得出Xf 和 Yf的位移 ,如下:Clearl=1;T=linspace(0,60,3000);fa=T.*10*pi/60xf=-0.5*l.*sin(fa); % velocity in the direction of xfyf=0.5*l.*cos(fa)-1.5*l; % velocity in the direction of yffor n=1:3000theta2
Matlab 正态分布
已知 Matlab 程序 得出Xf 和 Yf的位移 ,如下:
Clear
l=1;
T=linspace(0,60,3000);
fa=T.*10*pi/60
xf=-0.5*l.*sin(fa); % velocity in the direction of xf
yf=0.5*l.*cos(fa)-1.5*l; % velocity in the direction of yf
for n=1:3000
theta2(n)=atan2(sqrt(4*l^4-(xf(n)^2+yf(n)^2-2*l^2)^2),xf(n)^2+yf(n)^2-2*l^2);
a(n)=-l*sin(theta2(n));
b(n)=l+l*cos(theta2(n));
theta1(n)=atan2(b(n),a(n))-atan2(sqrt(a(n)^2+b(n)^2-xf(n)^2),xf(n));
end
plot(T,theta2);grid on;
hold on
plot(T,theta1,'--');grid on;
title('the angles of hip joint and knee joint against time respectively')
xlabel('Time Unit:Second')
ylabel('Angle in radians')
如何才能在matlab中实现 normally distributed random vibrations of 0.01 tandard deviation.同时Discuss how the vibration is propagated and its implications.
我好想没有分数
Matlab 正态分布 已知 Matlab 程序 得出Xf 和 Yf的位移 ,如下:Clearl=1;T=linspace(0,60,3000);fa=T.*10*pi/60xf=-0.5*l.*sin(fa); % velocity in the direction of xfyf=0.5*l.*cos(fa)-1.5*l; % velocity in the direction of yffor n=1:3000theta2
在MATLAB命令窗口输入randtool然后就出来个图形 额 貌似不能粘贴 只能口述了
下面的编辑窗口中有Mu和Sigma 就是正态分布的那两个参数 你改变那两个参数就够了
Discuss how the vibration is propagated and its implications.这个我是不是很懂 你可以试试disttool