如果(x^2-x)(x^2-x+5)+6=(x^2-x)^2+5(x^2-x)^2+6 那么,怎么分解因式(a^2-4a+5)(a^2-4a-6)+10

来源：学生作业帮助网编辑：作业帮时间：2024/11/27 23:24:45

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如果(x^2-x)(x^2-x+5)+6=(x^2-x)^2+5(x^2-x)^2+6 那么,怎么分解因式(a^2-4a+5)(a^2-4a-6)+10
如果(x^2-x)(x^2-x+5)+6=(x^2-x)^2+5(x^2-x)^2+6 那么,怎么分解因式(a^2-4a+5)(a^2-4a-6)+10

如果(x^2-x)(x^2-x+5)+6=(x^2-x)^2+5(x^2-x)^2+6 那么,怎么分解因式(a^2-4a+5)(a^2-4a-6)+10
(a²-4a+5)(a²-4a-6)+10
=（a²-4a）²-(a²-4a)-30+10
=(a²-4a)²-(a²-4a)-20
=(a²-4a-5)(a²-4a+4)
=(a-5)(a+1)(a-2)²

(x^2-x)(x^2-x+5)+6=(x^2-x)^2+5(x^2-x)^2+6=(x²-x+2)(x²-x+3)
(a^2-4a+5)(a^2-4a-6)+10
=(a²-4a)²-(a²-4a)-20
=(a²-4a+4)(a²-4a-5)
=(a-2)²(a+1)(a-5)

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