好象是六次的!速求(1/4-1/(4x))((2(根号6)-2)x^3-5/4+(5/4)x)=(-2/5+2/(5x)-(3/5)x^2)(2(根号6)-2)x^4
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 06:13:06
![好象是六次的!速求(1/4-1/(4x))((2(根号6)-2)x^3-5/4+(5/4)x)=(-2/5+2/(5x)-(3/5)x^2)(2(根号6)-2)x^4](/uploads/image/z/10201574-38-4.jpg?t=%E5%A5%BD%E8%B1%A1%E6%98%AF%E5%85%AD%E6%AC%A1%E7%9A%84%21%E9%80%9F%E6%B1%82%281%2F4-1%2F%284x%29%29%28%282%28%E6%A0%B9%E5%8F%B76%29-2%29x%5E3-5%2F4%2B%285%2F4%29x%29%3D%28-2%2F5%2B2%2F%285x%29-%283%2F5%29x%5E2%29%282%28%E6%A0%B9%E5%8F%B76%29-2%29x%5E4)
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好象是六次的!速求(1/4-1/(4x))((2(根号6)-2)x^3-5/4+(5/4)x)=(-2/5+2/(5x)-(3/5)x^2)(2(根号6)-2)x^4
好象是六次的!速求
(1/4-1/(4x))((2(根号6)-2)x^3-5/4+(5/4)x)=(-2/5+2/(5x)-(3/5)x^2)(2(根号6)-2)x^4
好象是六次的!速求(1/4-1/(4x))((2(根号6)-2)x^3-5/4+(5/4)x)=(-2/5+2/(5x)-(3/5)x^2)(2(根号6)-2)x^4
一般来说不大可能出现这种情况,会不会是前面算错了!最好检查下!
我去,你化成两个三次的,然后用MATLAB求吧