求函数极值点和极值(1)y=4-3x-x2 (2)f(x)=-4x3+3x2+6x+2 (3)f(x)=x2e(-x) (4)f(x)=2x3+3x2-12x-1要先求定义域!
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![求函数极值点和极值(1)y=4-3x-x2 (2)f(x)=-4x3+3x2+6x+2 (3)f(x)=x2e(-x) (4)f(x)=2x3+3x2-12x-1要先求定义域!](/uploads/image/z/10211219-35-9.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0%E6%9E%81%E5%80%BC%E7%82%B9%E5%92%8C%E6%9E%81%E5%80%BC%EF%BC%881%EF%BC%89y%3D4-3x-x2+%282%29f%EF%BC%88x%EF%BC%89%3D-4x3%2B3x2%2B6x%2B2+%283%29f%28x%29%3Dx2e%28-x%29+%284%29f%28x%29%3D2x3%2B3x2-12x-1%E8%A6%81%E5%85%88%E6%B1%82%E5%AE%9A%E4%B9%89%E5%9F%9F%21)
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