(x+y)(x-y)+4(y-1)x^2y^2-4xy-x^2-y^2+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 07:21:34
![(x+y)(x-y)+4(y-1)x^2y^2-4xy-x^2-y^2+1](/uploads/image/z/10215020-20-0.jpg?t=%28x%2By%29%28x-y%29%2B4%28y-1%29x%5E2y%5E2-4xy-x%5E2-y%5E2%2B1)
xQm0\BA"EH%HE*#c!@$)E3̔P é{n{/{1 5$#
eMX]?F%Qە؆#P+AP*_4+0yfmwJ5՝qtW>f4Kۣפ7TKD&v[>w-P<艞nTؐ
(x+y)(x-y)+4(y-1)x^2y^2-4xy-x^2-y^2+1
(x+y)(x-y)+4(y-1)
x^2y^2-4xy-x^2-y^2+1
(x+y)(x-y)+4(y-1)x^2y^2-4xy-x^2-y^2+1
(x+y)(x-y)+4(y-1)
=x²-y²+4y-4
=x²-(y²-4y+4)
=x²-(y-2)²
=[x-(y-2)][x+(y-2)]
=(x-y+2)(x+y-2)
x²y²-4xy-x²-y²+1
=(x²y²-2xy+1)-(x²+2xy+y²)
=(xy-1)²-(x+y)²
=[(xy-1)+(x+y)][(xy-1)-(x+y)]
=(xy+x+y-1)(xy-x-y-1)
(x+y-2)(x-y+2)
(xy-1+x+y)(xy-1-x-y)
(1)原式=x^2-y^2+4y-4=x^2-(y-2)^2=(x+y-2)(x-y+2)
(2)原式=(x^2y^2-2xy+1)-x^2-y^2-2xy =(xy-1)^2-(x+y)2=(xy-1-x-y)(xy-1+x+y)
x^2-(y-2)^2
(x^2-1)(y^2-1)-4xy