直线y=二分之一x+1与y轴交与点A,与x轴交与点D,抛物线y=二分之一x2+bx+c与直线交与A,E两点,与x轴交与B,C两点,且点B的坐标为【1,0】【1】求抛物线的解析式;【2】动点P在x轴上移动,当△PAE是直角
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 21:09:41
![直线y=二分之一x+1与y轴交与点A,与x轴交与点D,抛物线y=二分之一x2+bx+c与直线交与A,E两点,与x轴交与B,C两点,且点B的坐标为【1,0】【1】求抛物线的解析式;【2】动点P在x轴上移动,当△PAE是直角](/uploads/image/z/1023401-65-1.jpg?t=%E7%9B%B4%E7%BA%BFy%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80x%2B1%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E4%B8%8E%E7%82%B9A%2C%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%B8%8E%E7%82%B9D%2C%E6%8A%9B%E7%89%A9%E7%BA%BFy%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80x2%2Bbx%2Bc%E4%B8%8E%E7%9B%B4%E7%BA%BF%E4%BA%A4%E4%B8%8EA%2CE%E4%B8%A4%E7%82%B9%2C%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%B8%8EB%2CC%E4%B8%A4%E7%82%B9%2C%E4%B8%94%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%E4%B8%BA%E3%80%901%2C0%E3%80%91%E3%80%901%E3%80%91%E6%B1%82%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%9B%E3%80%902%E3%80%91%E5%8A%A8%E7%82%B9P%E5%9C%A8x%E8%BD%B4%E4%B8%8A%E7%A7%BB%E5%8A%A8%2C%E5%BD%93%E2%96%B3PAE%E6%98%AF%E7%9B%B4%E8%A7%92)
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