先化简,再求值(x+1/(x²-x)-x/(x²-2x-1))÷1/x,其中x=根号2+1要过程
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先化简,再求值(x+1/(x²-x)-x/(x²-2x-1))÷1/x,其中x=根号2+1要过程
先化简,再求值(x+1/(x²-x)-x/(x²-2x-1))÷1/x,其中x=根号2+1
要过程
先化简,再求值(x+1/(x²-x)-x/(x²-2x-1))÷1/x,其中x=根号2+1要过程
x+1/x除以(x- 1+x²/2x)
=(x+1)/x÷(2x^2-1-x^2)/2x
=2(x+1)/(x^2-1)
=2(x+1)/(x+1)(x-1)
=2/(x-1)
已知x=√2+1 x-1=√2
代入得原式=2/√2=√2