已知A=x³-2x²+4x+3,B=x²+2x-6,C=x³+2x-3,求A-(B+C)的值,其中x=-2当x=-5/2,y=2/5时,求代数式xy+2y²+(x²-3xy-2y²)-(x²-xy)的值
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![已知A=x³-2x²+4x+3,B=x²+2x-6,C=x³+2x-3,求A-(B+C)的值,其中x=-2当x=-5/2,y=2/5时,求代数式xy+2y²+(x²-3xy-2y²)-(x²-xy)的值](/uploads/image/z/1024653-21-3.jpg?t=%E5%B7%B2%E7%9F%A5A%3Dx%26%23179%3B-2x%26%23178%3B%2B4x%2B3%2CB%3Dx%26%23178%3B%2B2x-6%2CC%3Dx%26%23179%3B%2B2x-3%2C%E6%B1%82A-%28B%2BC%29%E7%9A%84%E5%80%BC%2C%E5%85%B6%E4%B8%ADx%3D-2%E5%BD%93x%3D-5%2F2%2Cy%3D2%2F5%E6%97%B6%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8Fxy%2B2y%26%23178%3B%2B%EF%BC%88x%26%23178%3B-3xy-2y%26%23178%3B%EF%BC%89-%EF%BC%88x%26%23178%3B-xy%EF%BC%89%E7%9A%84%E5%80%BC)
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已知A=x³-2x²+4x+3,B=x²+2x-6,C=x³+2x-3,求A-(B+C)的值,其中x=-2当x=-5/2,y=2/5时,求代数式xy+2y²+(x²-3xy-2y²)-(x²-xy)的值
已知A=x³-2x²+4x+3,B=x²+2x-6,C=x³+2x-3,求A-(B+C)的值,其中x=-2
当x=-5/2,y=2/5时,求代数式xy+2y²+(x²-3xy-2y²)-(x²-xy)的值
已知A=x³-2x²+4x+3,B=x²+2x-6,C=x³+2x-3,求A-(B+C)的值,其中x=-2当x=-5/2,y=2/5时,求代数式xy+2y²+(x²-3xy-2y²)-(x²-xy)的值
标题那题:
A-(B+C)=x³-2x²+4x+3-((x²+2x-6)+(x³+2x-3))=-3(x+2)(x-2)=0
另一题:
xy+2y²+(x²-3xy-2y²)-(x²-xy)=xy+2y²+x²-3xy-2y²-x²+xy=-xy=(-5/2)(2/5)=-1