√a²-3a+1 +b²+2b+1=0,则a²+1/a²-b=?(减去b的绝对值)
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√a²-3a+1 +b²+2b+1=0,则a²+1/a²-b=?(减去b的绝对值)
√a²-3a+1 +b²+2b+1=0,则a²+1/a²-b=?(减去b的绝对值)
√a²-3a+1 +b²+2b+1=0,则a²+1/a²-b=?(减去b的绝对值)
√a²-3a+1 +b²+2b+1=0
√a²-3a+1+(b+1)²=0
a²-3a+1=0
b=-1
a²+1/a²-b=a²+1/a²+1=1