作业帮第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/28 20:54:08
![第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=](/uploads/image/z/1024926-6-6.jpg?t=%E7%AC%AC%E5%8D%81%E5%85%AD%E7%AB%A0+%E5%88%86%E5%BC%8F1.%5B%28x-1%29%2F%28x%26%23178%3B-x-2%29%5D%26%23178%3B%C3%B7%E3%80%90%28x%26%23178%3B-2x%2B1%29%2F%282-x%29%E3%80%91%C3%B7%5B1%2F%28x%26%23178%3B%2Bx%29%5D%3D2.%5B%28a%26%23178%3B-5a%2B6%29%2F%28a%26%23178%3B-16%29%5D%C3%97%5B%28a%26%23178%3B%2B5a%2B4%29%2F%28a%26%23178%3B-4%29%5D%C3%B7%5B%28a-3%29%2F%28a%2B4%29%5D%3D)
xՓjA_%D*
!;_͍E 23fF\Ƌ*TBU/#DE I} 'iD
7g9ai8:<(M^\+[F5f*}tދJs^ԫ}ȬfX72y
5
y!Yo}ea9ymڰv v;NDYI;Q{[B%QMF[ kA(Xe! tp, a`bc!ep7(R,XK eiVc8'Ȋ;%Y=?Z/i摃H: Idb4 I
X8K Q &D1uJX2,"P53p.&%Y@d]{Oxq~xfWoݓao;|]
}?TY7
第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
第十六章 分式
1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=
2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
第十六章 分式1.[(x-1)/(x²-x-2)]²÷【(x²-2x+1)/(2-x)】÷[1/(x²+x)]=2.[(a²-5a+6)/(a²-16)]×[(a²+5a+4)/(a²-4)]÷[(a-3)/(a+4)]=
1.
2.
这里的a用x代替.
这个是经过几何画板验算的