若x^2+y^2-6x+4y+13=0,则x^y等于多少

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若x^2+y^2-6x+4y+13=0,则x^y等于多少
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若x^2+y^2-6x+4y+13=0,则x^y等于多少
若x^2+y^2-6x+4y+13=0,则x^y等于多少

若x^2+y^2-6x+4y+13=0,则x^y等于多少
x^2+y^2-6x+4y+13=(x-3)^2+(y-2)2=0
x=3
y=2
3^2=9

x=3 y=-2
x^y=1/9

x^2+y^2-6x+4y+13
=(x^2-6x+9)+(y^2+4y+4)
=(x-3)^2+(y+2)^2
=0
=>
x=3,y=-2
x^y=1/9

x^2+y^2-6x+4y+13=(x-3)^2+(y-2)^2=0
(x-3)^2=(y-2)^2=0
x=3
y=2
3^2=9

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