作业帮1.已知x/y=1/2,则x^2-3xy+2y^2的值为?2.m^3-m-2=0,则(m^3/m+2)-[(m^3-m)/2]=?
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![1.已知x/y=1/2,则x^2-3xy+2y^2的值为?2.m^3-m-2=0,则(m^3/m+2)-[(m^3-m)/2]=?](/uploads/image/z/10253571-51-1.jpg?t=1.%E5%B7%B2%E7%9F%A5x%2Fy%3D1%2F2%2C%E5%88%99x%5E2-3xy%2B2y%5E2%E7%9A%84%E5%80%BC%E4%B8%BA%3F2.m%5E3-m-2%3D0%2C%E5%88%99%28m%5E3%2Fm%2B2%29-%5B%28m%5E3-m%29%2F2%5D%3D%3F)
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1.已知x/y=1/2,则x^2-3xy+2y^2的值为?2.m^3-m-2=0,则(m^3/m+2)-[(m^3-m)/2]=?
1.已知x/y=1/2,则x^2-3xy+2y^2的值为?
2.m^3-m-2=0,则(m^3/m+2)-[(m^3-m)/2]=?
1.已知x/y=1/2,则x^2-3xy+2y^2的值为?2.m^3-m-2=0,则(m^3/m+2)-[(m^3-m)/2]=?
x/y=1/2,y=2x
x^2-3xy+2y^2=(y-x)(2y-x)=3x^2
m^3-m-2=0,m^3＝m＋2,m^3-m＝2
(m^3/m+2)-[(m^3-m)/2]=1－1＝0
x^2-3xy+2y^2 = x^2 - 6x^2 + 8x^2 = 3x^2
m^3 = m+2
==> (m^3/m+2)-[(m^3-m)/2] = [(m+2)/m+2] - [2/2] = [3+2/m] - 1 = 2 + 2/m
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